Question

which of the following is the the correct factorization of this trinomial.
-3x^2-10x-8

a) (-3x+4)(x-2)
b) -(x+4)(x-3)
c)-(3x+4)(x+2)
d) -3(x+4)(x+2)

Answer 1

$-3x^2-10x-8 = - (3x^2 +10x+8 ) = - (3x^2 +6x +4x+8) =\\ \\=-[3x(x+2)+4(x+2)]= - (3x+4) (x+2) \\ \\Answer : \ c)\ \ \ -(3x+4)(x+2)$

Answer 2

$-3x^2-10x-8=-3x^2-4x-6x-8=-x(3x+4)-2(3x+4)\\\\=(3x+4)(-x-2)=-(3x+4)(x+2)$