[tex]64^{\text{x}} = (8^2)^{\text{x}} = 8^{2\text{x}}[/tex]
The rule used is that [tex](a^b)^c = a^{bc}[/tex] we multiply the exponents b and c.
Or we could say this
[tex]64^{\text{x}} = (4^3)^{\text{x}} = 4^{3\text{x}}[/tex]
Or,
[tex]64^{\text{x}} = (2^6)^{\text{x}} = 2^{6\text{x}}[/tex]
Therefore, we have multiple possible answers.