The point which would lie on the graph of f(x) = log2x is; (1, 0.301).
Since it follows from the task content that the given point (–1, 0.5) lies on the graph of f –1(x) = 2x.
The subsequent graph of f(x) = log2x would result from taking logarithms in which case, we have the graph passing through points determined as follows;
f(x) = log2^x
f(x) = x log2
Hence, when x = 1;
f(1) = 1log 2
Hence, we have point; (1, 0.301).
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