Question

The product of a number and 3 less than the number is 40. Find the number.

Answer 1

By solving a quadratic equation we will see that the number can be:

8 or -5.

How to find the number?

The product of a number N, and 3 less than the number, is equal to 40.

This is written as:

$N*(N - 3) = 40$

Now we need to solve this for N.

$N^2 - 3N = 40$

$N^2 - 3N - 40 = 0$

Then we need to solve this quadratic equation:

$N = \frac{-(-3) \pm \sqrt{(-3)^2 - 4*1*(-40)} }{2} \\\\N = \frac{3 \pm 13 }{2}$

Then we have two solutions:

• N = (3 - 13)/2 = -5
• N = (3 + 13)/2 = 8

These are the two possible solutions.

If you want to learn more about quadratic equations:

https://brainly.com/question/1214333

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