Using a discrete distribution, the expected value for this game is of -$1.298, which means that each time he plays, he is expected to lose $1.298.
The expected value of a discrete distribution is given by the sum of each outcome multiplied by it's respective probability.
Considering the situation described in this problem, the distribution for the earnings is given as follows:
Hence the expected value is given as follows:
[tex]E(X) = 700\frac{1}{1000} - 2\frac{999}{1000} = \frac{700 - 2(999)}{1000} = -1.298[/tex]
The expected value for this game is of -$1.298, which means that each time he plays, he is expected to lose $1.298.
More can be learned about the expected value of a discrete distribution at https://brainly.com/question/3316979
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