A block of mass 0.248 kg is placed on top of a light, vertical spring of force constant 5 025 N/m and pushed downward so that the spring is compressed by 0.090 m. After the block is released from rest, it travels upward and then leaves the spring. To what maximum height above the point of release does it rise

The force exerted by a spring on objects attached to its ends is proportional to the spring's change in length away from its equilibrium length.

F(spring) = k*x

here,

mass, m=0.240 kg

vertical spring constant, k = 5050 N/m

compression, x=0.090 m

When the spring is compressed, the spring potential energy is:

E = (k*x^2) / 2

substituting the values,

E = 5050* 0.090^2 / s

E = 20.91 J

This energy would be converted to kinetic, so the mass gains speed, which is then converted to gravitational potential energy once the mass reaches its highest point

E(p) = m*g*h

where, h is the maximum height

E(p) = E

m*g*h = 20.91

h = 20.91 / ( 9.8 * 0.248 )

h = 8.82 m

hence

The maximum height above the point of release is 8.82 m

Learn more about spring force here:

https://brainly.com/question/14655680

#SPJ4