The percentage of great lakes states would we expect the economic impact from fishing to be between $234.5 and $401.5 is 50%.
Given that mean is $318 , standard deviation is $83.5 and confidence interval is $234.5 and $401.5.
We have to calculate the percentage of great lakes that we would expect the economic impact from fishing to be between $234.5 and $401.5.
Because we have not given the sample size taken so we will use any test.We are using z test.
We know that,
z=X-μ/σ
where μ is population mean and σ is population standard deviation.
We cannot find p value between $234.5 and $401.5. We have to find the p value between $234.5 and $318 and then add the p value between $318 and $401.5 by calculating.
P value between $234.5 and $318:
z=234.5-318/83.5
=-83.5/83.5
=-1
p value of -1 is 0.1587
P value between $318 and $401.5:
z=401.5-318.5/83.5
=83.5/83.5
=1
p value of z=1 is 0.3413
Total p value=0.1587+0.3413
=0.5
Total percentage=0.5*100
=50%
Hence the percentage that we would expect the impact to be between $234.5 and $401.5 is 50%.
Learn more about z test at https://brainly.com/question/14453510
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