Respuesta :

Answer:

x = 4 or x = -3/2

Step-by-step explanation:

To simplify and solve this, let's use the quadratic formula.

So the format of a quadratic equation is supposed look like this:

[tex]ax^2+bx+c=0[/tex]

Let's find a, b, c:

  • a is the coefficient of x^2
  • b is the coefficient of x
  • c is the constant term

Now let's solve the equation.

Let's solve your equation step-by-step.

2x^2−5x−12=0

For this equation: a=2, b=-5, c=-12

2x^2+−5x+−12=0

Step 1: Use quadratic formula with a=2, b=-5, c=-12.

[tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

[tex]x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-12)} }{2(2)}[/tex]

[tex]x=\frac{5\pm\sqrt{121} }{4}[/tex]

[tex]x=4[/tex] or [tex]x=\frac{-3}{2}[/tex]

Answer:

x = 4 or x = -3/2

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