54.0 g Al reacts with 64.0 g O2 to
form Al2O3 according to the equation.
4A1+30₂ → 2Al2O3
Al: 26.98 g/mol Al2O3: 101.96 g/mol
How many grams of Al2O3 form
from 54.0 g Al?
[?] g Al₂O3

540 g Al reacts with 640 g O2 to form Al2O3 according to the equation 4A130 2Al2O3 Al 2698 gmol Al2O3 10196 gmol How many grams of Al2O3 form from 540 g Al g Al class=

Respuesta :

Answer:

102 g Al₂O₃

Explanation:

To find the mass of Al₂O₃, you need to (1) convert grams Al to moles Al (via molar mass), then (2) convert moles Al to moles Al₂O₃ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Al₂O₃ to grams Al₂O₃ (via molar mass). It is important to arrange the ratios in a way that allows for the cancellation of units. The final answer should have 3 sig figs to reflect the given values.

Molar Mass (Al): 26.98 g/mol

Molar Mass (Al₂O₃): 101.96 g/mol

4 Al + 3 O₂ ---> 2 Al₂O₃

54.0 g Al          1 mole             2 moles Al₂O₃         101.96 g
--------------  x  -----------------  x  -----------------------  x  ----------------  =  102 g Al₂O
                        26.98 g               4 moles Al            1 mole

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