Respuesta :

1

Step-by-step explanation:

when we put 1 in the equation the nominator becomes zero and it becomes undefined

Hii!

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[tex]\stackrel\star\rightsquigarrow\circ\boldsymbol{\underbrace{Answer:}}}\circ\leftharpoonup[/tex]

The value of x should be 5! ^^

[tex]\stackrel\star{\rightsquigarrow\circ\boldsymbol{\underbrace{Explanation:}}}\circ\leftharpoonup[/tex]

[tex]\boxed{\\\begin{minipage}{7cm} For\,an\,expression \\ \boldsymbol{to\,be\,und efined,} \\ \,its\,denominator\,should\,be\,zero \end{minipage}}}[/tex]

Remember this! ^^

Now let's consider this:

Which value of x will make the denominator equal to 0?

Is it 1? If we stick 1 in, we will not obtain 0.

[tex]\twoheadrightarrow\sf y=\cfrac{3\cdot1-3}{1-5}[/tex]

[tex]\bullet[/tex] Simplify this

[tex]\twoheadrightarrow\sf y=\cfrac{3-3}{-4}[/tex]

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We will obtain 0 in the numerator, but not in the denominator; if the numerator is 0, then the fraction, or fractional expression, is 0.

Let's try 5. 5-5 is equal to 0, so this sounds promising! ^^

[tex]\twoheadrightarrow\sf y=\cfrac{3\cdot5-3}{5-5}[/tex]

[tex]\bullet[/tex] Look what we obtain when we simplify

Don't we obtain 15-3/0?

Like I said above, if an expression has 0 as its denominator, it's undefined.

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Hope that this helped! Best wishes.

[tex]\textsl{Reach far. Aim high. Dream big.}[/tex]

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