A 66.0 kg diver is 2.30 m above the water, falling at speed of 2.20 m/s. Calculate her kinetic energy as she hits the water. (Neglect air friction)

Respuesta :

The kinetic energy of the diver as she hits the water is 159.72J. Details about kinetic energy can be found below.

How to calculate kinetic energy?

The kinetic energy of a body can be calculated using the following formula:

K.E = ½ × m × v²

Where;

  • K.E = kinetic energy
  • m = mass
  • v = velocity

According to this question, a 66.0 kg diver is 2.30 m above the water and falls at speed of 2.20 m/s.

Kinetic energy = ½ × 66 × 2.2²

K.E = 159.72J

Therefore, the kinetic energy of the diver as she hits the water is 159.72J.

Learn more about kinetic energy at: https://brainly.com/question/12669551

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