Using sine rule the value of angle N in the triangle is 61 degrees.
How to find angle of a triangle using sine rule?
Using sine rule
MO / sin N = MN / sin ∠O
Therefore,
MO = 18
MN = 6
∠O = 17°
Hence,
18 / sin N = 6 / sin 17
cross multiply
18 sin 17 = 6 sin N
divide both sides by 6
sin N = 5.26269068501 / 6
sin N = 0.87711511416
N = sin⁻¹ 0.87711511416
N = 61.296295658
∠N ≈ 61°
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