Question

To determine the molar mass of a certain protein, 2.00×10-3 g of it was dissolved in enough water to
make 1.00 mL of solution. The osmotic pressure of this solution was found to be 2.24 torr at 25.0 o
C.
Calculate the molar mass of the protein.

Answer 1

The molar mass of the protein from the calculation is 1667 g/mol.

What is osmotic pressure?

The osmotic pressure can be determined using the formula;

π=icRT

i = Van't Hoff factor = 1

c = concentration = ?

R = gas constant = 0.082 atmLK-1mol-1

T = temperature = 298 K

π= 2.24 torr or 0.029 atm

Now;

0.029 = 1 * c * 0.082 * 298

c = 0.029/1 * 0.082 * 298

c = 0.0012 M

Now;

2.00×10-3 g/MM = 0.0012 M *  1.00/1000L

MM = 2.00×10-3 g/0.0012 M *  1.00/1000L

MM = 1667 g/mol

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