Question

Ammonia reacts with oxygen to produce nitric acid (HNO3) and water. What mass of nitric acid, in grams, can be made from 405 g of ammonia?
Express the mass to three significant figures and include the appropriate units.

Answer 1

Answer:

1501 g = 15.0 x 10² g (3 significant figures).

Explanation:

• The balanced equation for the mentioned reaction is:

NH₃(g) + 2O₂(g) → HNO₃(aq) + H₂O(aq),

It is clear that 1.0 moles of NH₃ react with 2.0 moles of O₂ to produce 1.0 mole of HNO₃ and 1.0 moles of H₂O.

• Firstly, we need to calculate the no. of moles (n) of 405 g of NH₃:

n = mass/molar mass = (405 g)/(17.0 g/mol) = 23.82 mol.

using cross multiplication:

1.0 mol of NH₃ produces → 1.0 mol of HNO₃.

∴ 23.82 mol of NH₃ produces → 23.82 mol of HNO₃.

• Now, we can find the mass of NH₃ produced:

mass = n * molar mass = (23.82 mol) * (63.01 g/mol) = 1501 g = 15.0 x 10² g (3 significant figures).