Question

Please help me with my question thank you i appreciate it!!!!!

Answer 1

Answer:

Assuming that there are two different fractions:

Probability of rolling a sum of 12 = $\frac{1}{36}$

Probability of rolling a sum of 11 = $\frac{2}{36}$

Step-by-step explanation:

To find probability (p)

$p(event)=\frac{number of favorable outcomes}{number of possible outcoumes}$

All of the possible sums of 11 or 12:

For possible ways to make 11:

• 5,6  and  6,5

For possible ways to make 12:

• 6,6

All of the possible outcomes in total are 36

All of the possible outcomes to roll a sum of 11 are 2

All of the possible outcomes to roll a sum of 12 are 1

Form the fraction for each

$p(of rolling a 12)= \frac{1}{36}$

$p(of rolling an 11)= \frac{2}{36}$

Simplify if necessary and you are good to go!

Hope this helps and feel free to comment, give feedback, ask questions, and correct if I'm wrong!

Answer 2

Answer:

Assuming that there are two different fractions:

Probability of rolling a sum of 12 = \frac{1}{36}

36

1

Probability of rolling a sum of 11 = \frac{2}{36}

36

2

Step-by-step explanation:

To find probability (p)

p(event)=\frac{number of favorable outcomes}{number of possible outcoumes}p(event)=

numberofpossibleoutcoumes

numberoffavorableoutcomes

All of the possible sums of 11 or 12:

For possible ways to make 11:

5,6 and 6,5

For possible ways to make 12:

6,6

All of the possible outcomes in total are 36

All of the possible outcomes to roll a sum of 11 are 2

All of the possible outcomes to roll a sum of 12 are 1

Form the fraction for each

p(of rolling a 12)= \frac{1}{36}p(ofrollinga12)=

36

1

p(of rolling an 11)= \frac{2}{36}p(ofrollingan11)=

36

2

Simplify if necessary and you are good to go!