Step-by-step explanation:
Firstly find the area if the parallelogram which is
=length of the base × vertical height
=
[tex]12m \times 5m[/tex]
=
[tex]60 {m}^{2} [/tex]
Now solve for the area of the circle
=
[tex]\pi {r}^{2} [/tex]
RADIUS = DIAMETER ÷2
[tex] \frac{4m}{2} [/tex]
=
[tex]2m[/tex]
so the area of the circle
=
[tex] \frac{22}{7} \times 2m \times 2m[/tex]
[tex] \frac{22}{7} \times 4 {m}^{2} [/tex]
[tex]12.57 {m}^{2} [/tex]
subtract the area of the circle from the parallelogram
=
[tex]60 {m }^{2} - 12.57 {m}^{2} [/tex]
=
[tex]47.43 {m}^{2} [/tex]
Done