Question

a stone is dropped from rest from a tall building how fast is the stone moving after 5s

Answer 1

Answer:

The final velocity is -49.05 meters per second.

Explanation:

Let's use an equation of constant acceleration:

$v=v_0+at\\v=v_0-gt$

Where a is the acceleration and g is the acceleration caused by gravity.

Since the object is being dropped from rest, $v_0=0 \frac{m}{s}$.

We're looking for the speed after 5 seconds, so $t=5 s$.

$v=(0\frac{m}{s})-(9.81\frac{m}{s^{2}})(5s)\\v=-49.05\frac{m}{s}$

So the final velocity is -49.05 meters per second.