Question

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A jar contains 11 green marbles, 6 red marbles, and 9 blue marbles. A marble is selected at random, not replaced, and then a second marble is selected. What is the probability of selecting a red marble followed by a green marble?

Answer 1

Answer:

red marbel

$= \frac{3}{13}$

green marbel

$= \frac{9}{26}$

Step-by-step explanation:

for the red marbel you first add all the number of balls given and the total is 26 then you take the number of red marbels dividing the total number of all the balls and if you are able to cancel out you can and there you get your answer same applies to the green marbel

Answer 2

The key phrase here is “not replaced”
The probability of choosing red first is 6/26
There are only 25 marbles left!
The probability of now picking green is 11/25.
So P(Red then Green) = 6/26 x 11/25 = 66/650 = 33/325