Question

What is limit of startfraction x squared x minus 12 over x squared minus 3 x endfraction as x approaches 3? 0 startfraction 7 over 3 endfraction 4 dne

Answer 1

The limit of the expression $f(x) = \frac{x^2 - 12}{x^2 - 3}$a s x approaches 3 is -1/2

How to determine the limit?

The expression is given as:

$f(x) = \frac{x^2 - 12}{x^2 - 3}$

As the variable x approaches 3, the limit is represented as:

$\lim_{x \to 3} f(x)$

So, we have:

$\lim_{x \to 3} = \frac{3^2 - 12}{3^2 - 3}$

Evaluate the exponents

$\lim_{x \to 3} = \frac{-3}{6}$

Evaluate the quotient

$\lim_{x \to 3} = -\frac{1}{2}$

Hence, the limit of the expression as x approaches 3 is -1/2

Read more about limits at:

https://brainly.com/question/5313449

#SPJ4