Respuesta :

as far as I can tell, it's simply asking for what reference angle does 120° have?

check the picture below. Keeping in mind that on the II Quadrant, the secant will be negative.

Ver imagen jdoe0001

Hello!

This question is referring to reference angles.

In Quadrant I, then 0° < θ < 90°.

In Quadrant II, then 90° < θ < 180°.

In Quadrant III, then 180° < θ < 270°.

In Quadrant IV, then 270° < θ < 360°.

Here are the reduction formulas:

In Quadrant I: θ (The angle doesn't change because in Q1, the angle is acute.)

In Quadrant II: (180 - θ)

In Quadrant III: (180 + θ)

In Quadrant IV: (360 - θ).

Since sec 120° is located in quadrant one, we use the reduction formula: (180 - θ).

(180 - 120) = 60°

Therefore, the angle that can be used to evaluate sec 120°, is C, 60°.

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