The value of "a" if the area (in square units) of the region under the curve of the function f(x)=5 , on the interval from x=a to x=8 is 20 square units is 4
The given horizontal line is y = f(x) = 5 while the interval x=a and x= 8 represent vertical lines that intersect x = a and x = 8.
The area above the x-axis that is bound by f(x) on the top and x=a and x=8 on the sides is a rectangle with width of 5units and length (8 - a)units.
The area pf the rectangle is expressed as:
Area = length * width
Substitute
20 = 5(8-a)
(8-a) = 20/5
8-a = 4
-a = 4 - 8
-a = -4
a = 4
Hence the value of "a" if the area (in square units) of the region under the curve of the function f(x)=5 , on the interval from x=a to x=8 is 20 square units is 4
Correct question;
If the area (in square units) of the region under the curve of the function f(x)=5 , on the interval from x=a to x=8 is 20 square units, what is the value of a?
Answers: 4, 5, 6, 7, or 8?
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