The percentage, by mass, of fluorine in sulfur hexafluoride (SF6), a potent greenhouse gas is 13.008%.
The percentage by mass of an element in a compound can be calculated by dividing the atomic mass of the element by the compound, multiplied by 100.
According to this question, the percentage by mass of fluorine (F) in sulfur hexafluoride (SF6) is to be calculated as follows:
% mass of F = 19/146.06 × 100
% mass of F = 13.008%
Therefore, the percentage, by mass, of fluorine in sulfur hexafluoride (SF6), a potent greenhouse gas is 13.008%.
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