Select the correct answer. Exponential function f is represented by the table. x -2 -1 0 1 2 f(x) -46 -22 -10 -4 -1 Function g is represented by the equation. Which statement correctly compares the two functions on the interval [-1, 2]? A. Only function f is increasing, and only function f is negative. B. Both functions are increasing, but function f increases at a faster average rate. C. Only function f is increasing, but both functions are negative. D. Both functions are increasing, but function g increases at a faster average rate.Select the correct answer. Exponential function f is represented by the table. x -2 -1 0 1 2 f(x) -46 -22 -10 -4 -1 Function g is represented by the equation. Which statement correctly compares the two functions on the interval [-1, 2]? A. Only function f is increasing, and only function f is negative. B. Both functions are increasing, but function f increases at a faster average rate. C. Only function f is increasing, but both functions are negative. D. Both functions are increasing, but function g increases at a faster average rate.

Respuesta :

Both functions are increasing, but function g increases at a faster average rate.

What is a function?

A function is a statement, rule, or law that establishes the connection between two variables. In mathematics, functions are everywhere and are necessary for constructing physical connections.

Let f(x) = abĖ£ + c

At x = 0, f(0) = -10. Then we have

a + c = -10

Then similarly, by satisfying the above table in f(x) will be

[tex]\rm f(x) = - \dfrac{33}{5} \left ( \dfrac{1}{11} \right )^x - \dfrac{17 }{5} \\\\f'(x ) > 0[/tex]

Then we can say f(x) is an increasing function.

[tex]\rm g(x) = - 18 \left ( \dfrac{1}{3} \right )^x +2 \\\\g'(x ) > 0[/tex]

Then we can say g(x) is an increasing function.

More about the function link is given below.

https://brainly.com/question/5245372

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Answer:

The correct answer would be option D- Both functions are increasing, but function g increases at a faster average rate.

Hope this helps and good luck!

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