Answer:
The water she need is [tex]7\frac{7}{8} \ cups.[/tex] and strawberry syrup [tex]11\frac{13}{16}\ cups[/tex].
Step-by-step explanation:
Given:
Dina wants to make 15 3/4 cups of strawberry drink by mixing water and strawberry syrup with a ratio of 2 1/4 cup of water for every 3/4 cup of syrup.
Now, to find the quantity of water and syrup she need to use.
As given in question ratio so:
Strawberry syrup = 2 1/4 = 9/4.
Water = 3/4.
Total cups of strawberry drink = 15 3/4 = 63/4.
Let the strawberry syrup be [tex]\frac{9}{4} x[/tex].
And let the water be [tex]\frac{3}{4} x[/tex].
According to question:
[tex]\frac{9x}{4} + \frac{3x}{4}=\frac{63}{4}[/tex].
On adding the fractions:
⇒[tex]\frac{9x+3x}{4} =\frac{63}{4}[/tex]
⇒[tex]\frac{12x}{4} =\frac{63}{4}[/tex]
Multiplying both sides by 4 we get:
⇒[tex]12x=63[/tex]
Dividing both sides by 12 we get:
⇒[tex]x=\frac{63}{12}[/tex]
Dividing numerator and denominator by 3 on R.H.S we get:
⇒[tex]x=\frac{21}{4}[/tex]
Now, putting the value of [tex]x[/tex] on ratios:
Strawberry syrup = [tex]\frac{9}{4}\times x=\frac{9}{4}\times\frac{21}{4}[/tex]
= [tex]\frac{189}{16}[/tex]
= [tex]11\frac{13}{16}\ cups[/tex]
Water = [tex]\frac{3}{4}\times x =\frac{3}{4} \times\frac{21}{4}[/tex]
= [tex]\frac{63}{8}[/tex]
= [tex]7\frac{7}{8} \ cups.[/tex]
Therefore, the water she need is [tex]7\frac{7}{8} \ cups.[/tex] and strawberry syrup [tex]11\frac{13}{16}\ cups[/tex].