Dina wants to make 15 3/4 cups of strawberry drink by mixing water and strawberry syrup with a ratio of 2 1/4 cup of water for every 3/4 cup of syrup. how much water and syrup will she need ro use?

Respuesta :

Answer:

The water she need is [tex]7\frac{7}{8} \ cups.[/tex] and strawberry syrup [tex]11\frac{13}{16}\ cups[/tex].

Step-by-step explanation:

Given:

Dina wants to make 15 3/4 cups of strawberry drink by mixing water and strawberry syrup with a ratio of 2 1/4 cup of water for every 3/4 cup of syrup.

Now, to find the quantity of water and syrup she need to use.

As given in question ratio so:

Strawberry syrup = 2 1/4 = 9/4.

Water = 3/4.

Total cups of strawberry drink = 15 3/4 = 63/4.

Let the strawberry syrup be [tex]\frac{9}{4} x[/tex].

And let the water be [tex]\frac{3}{4} x[/tex].

According to question:

[tex]\frac{9x}{4} + \frac{3x}{4}=\frac{63}{4}[/tex].

On adding the fractions:

⇒[tex]\frac{9x+3x}{4} =\frac{63}{4}[/tex]

⇒[tex]\frac{12x}{4} =\frac{63}{4}[/tex]

Multiplying both sides by 4 we get:

⇒[tex]12x=63[/tex]

Dividing both sides by 12 we get:

⇒[tex]x=\frac{63}{12}[/tex]

Dividing numerator and denominator by 3 on R.H.S we get:

⇒[tex]x=\frac{21}{4}[/tex]

Now, putting the value of [tex]x[/tex] on ratios:

Strawberry syrup =  [tex]\frac{9}{4}\times x=\frac{9}{4}\times\frac{21}{4}[/tex]

                             =  [tex]\frac{189}{16}[/tex]

                             =  [tex]11\frac{13}{16}\ cups[/tex]  

Water = [tex]\frac{3}{4}\times x =\frac{3}{4} \times\frac{21}{4}[/tex]

          = [tex]\frac{63}{8}[/tex]

          = [tex]7\frac{7}{8} \ cups.[/tex]

Therefore, the water she need is [tex]7\frac{7}{8} \ cups.[/tex] and strawberry syrup [tex]11\frac{13}{16}\ cups[/tex].

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