many grams of potassium iodide (KI) should be used to prepare 0.600
of a 2.50 M solution of potassium iodide? (The mass of potassium is 39.10 grams
che mass of iodine is 126.90 g).
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1D
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498
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Respuesta :

The mass of the solute is given by the moles and the molar mass of that substance. In the 2.50 M solution, 249 gm of KI is present.

What is molarity?

Molarity and the volume of the solution can be used to give the moles of the solute dissolved in the solution and can be further used to give the mass of the solute.

Given,

Molarity of KI = 2.50M

Volume of potassium iodide solution = 0.6 L

Molar mass of KI = 166

The formula of molarity is given as:

Molarity = moles ÷ volume

The formula of moles is given as:

Moles = mass ÷ molar mass

Substituting moles into molarity as:

M = mass ÷ molar mass × Volume

mass = 2.50 × 0.6 × 166

= 249 gms

Therefore, 249 gms is the mass of KI.

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249 grams of potassium iodide (KI) should be used to prepare 0.600 of a 2.50 M solution of potassium iodide.

Define molarity of a solution.

Molarity (M) is the amount of a substance in a certain volume of solution.

Molarity is defined as the moles of a solute per litres of a solution.

Molarity is also known as the molar concentration of a solution.

Given data:

Molarity of the solution = 2.50 M

Volume of solution = 0.600 L

Molarity =  [tex]\frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]

Now putting the value in the equation:

2.50 M =  [tex]\frac{Moles \;solute}{ 0.600 L}[/tex]

Moles of solute = 1.5

Moles  = [tex]\frac{mass}{molar \;mass}[/tex]

1.5  = [tex]\frac{mass}{166.0028 }[/tex]

Mass  = 249 gram.

Hence, 249 grams of potassium iodide (KI) should be used to prepare 0.600 of a 2.50 M solution of potassium iodide.

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