Question

1.
The equation of the line having x-intercept -3/2, y-intercept 3/4 is
1) 3x + 2y - 6 = 0
2) 2x - 4y + 3 = 0
3) 2x + 3y - 5 = 0
4) 4x - 3y - 12 = 0
O
1)
2)
O
3)
O
4)​

Answer 1

Answer:

2nd option

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- $\frac{3}{2}$, 0) and (x₂, y₂ ) = (0, $\frac{3}{4}$ )

m = $\frac{\frac{3}{4}-0 }{0+\frac{3}{2} }$ = $\frac{\frac{3}{4} }{\frac{3}{2} }$ = $\frac{1}{2}$ and c = $\frac{3}{4}$ , then

y = $\frac{1}{2}$ x + $\frac{3}{4}$ ( multiply through  by 4 to clear the fractions )

4y = 2x + 3 ( subtract 4y from both sides )

0 = 2x - 4y + 3 , that is

2x - 4y + 3 = 0 ← equation of line