find the perpendicular line then find the intersection then find the point
perpendicular lines have slopes that are perpendicular
the slopes multiply bo -1
y=mx+b
m=slope
y=2x-3
2 is slope
2 times what=-1
what=-1/2
the equation is
y-3=-1/2(x-8) or
y=(-1/2)x+7
find intersection
at (4,5)
distance bwetweeen (8,3) and (4,5)
D=[tex] \sqrt{(8-4)^2+(3-5)^2} [/tex]
D=[tex] \sqrt{(4)^2+(-2)^2} [/tex]
D=[tex] \sqrt{16+4} [/tex]
D=[tex] \sqrt{20} [/tex]
D=2√5
distance= 2√5
