The minimum energy of the two oppositely directed gamma rays in a PET procedure is : 0.51 MeV
In a PET procedure when an electron and positron collide the energy equivalent of their individual masses are converted into gamma rays which will move in directions opposite to each other.
Given that an electron and a positron posses equal masses the minimum energy of the gamma ray will be 0.51MeV
Hence we can conclude that the minimum energy of the two oppositely directed gamma rays in a PET procedure is 0.51MeV.
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