Question

The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length.

Subtract the quotient when 20x⁴y² is divided by 5x³y from the product of 2x and 3y.
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Answer 1

Step-by-step explanation:

1) The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length....

= Solution ,

Length ( L ) = ?

breadth ( b ) = 10xy cm

area ( a ) = ( 30x² + 20xy )

Now ,

area ( a ) = l × b

or, ( 30x²y + 20xy ) = L × 10xy cm

$or,\frac{30 {xy + 20xy}^{2} }{10xy} = l$

$or, \: l = 3 {x}^{2 - 1} + 2cm$

$\boxed{\sf{l = (3x+2)cm}}$

2) Subtract the quotient when 20x⁴y² is divided by 5x³y from the product of 2x and 3y.

= Solution,

$= \frac{20 {x}^{4} {y}^{2} }{5 {x}^{3} y}$

$= 4xy$

The product of 3x and 4y = 6xy

= 6x - 4xy

$= \boxed{\sf {2xy}}$

hope it helped !!!!