Answer:
6 and -1
Step-by-step explanation:
If you take the equation and set it to be 0, you can find the input values that make it 0.
[tex]x^2-5x-6=0[/tex]
Since this is a quadratic, equation you can use the quadratic formula with the values:
The quadratic formula is:
[tex]x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]
If you plug the values for a, b, and c, you get:
x = 6 and x = -1