Calculate the quantity of energy produced per gram of U-235 (atomic mass = 235.043922 amu ) for the neutron-induced fission of U-235 to form Xe-144 (atomic mass = 143.9385 amu ) and Sr-90 (atomic mass = 89.907738 amu ).

Fission is the formation of two smaller atoms by the collision of the neutrons. The quantity of energy produced per gram is 7.23 × 10¹⁰ J/g.
Nuclear fission is a process in which the neutron collides with the atom and results in the formation of two isotopes.
The nuclear fission reaction is shown as,
[tex]\rm ^{235}_{92}U + ^{1}_{0} n \rightarrow ^{144}_{54} Xe + ^{90}_{38}Sr + 2^{1}_{0}n[/tex]
Energy in joules is calculated by the Einstein's formula as:
[tex]\begin{aligned} \rm E &= \rm mc^{2}\\\\&= 3.139 \times 10^{-28} \times (2.99 \times 10^{8})^{2}\\\\&= 2.82 \times 10^{-11}\;\rm J\end{aligned}[/tex]
Energy per gram is calculated as:
[tex]\begin{aligned}& =\dfrac{ (2.82 \times 10^{-11})(6.022 \times 10^{26})}{235.043}\\\\&= 0.0722 \times 10^{12}\\\\&= 7.23 \times 10^{10} \;\rm J/g\end{aligned}[/tex]
Therefore, the energy per gram of the fission is [tex]7.23 \times 10^{10} \;\rm J/g.[/tex]
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