The North and East forces are 90° apart, making a right triangle with the resultant as the hypotenuse.
(200)² + (410)² = F²
40,000 + 168,100 = F²
√(208,100) = F
456.18 N = F
F= ma
456.18 N = (300 kg)a
456.18 / 300kg = a
1.52 m/s² = a
The sailboat will be heading North East. To find the angle of the boats trajectory use inverse tangent function.
tan(Ф) = opposite/adjacent
arctan(opposite/adjacent) = Ф
arctan(410/200) = 64° North East
