Question

Which metal would cause the greatest increase in the temperature of the water in the calorimeter: the
one with the higher specific heat, or the one with the lower specific heat? Explain.

(THE EXPLANATION IS IMPORTANT)

Answer 1

Answer:

The one with higher specific heat

Explanation:

A metal with the highest specific heat will cause the greatest increase in temperature of water in a calorimeter because the metal would hold more heat, and then transfer it to the water.

Answer 2

Answer:

$\sf \: \fbox{Metal \: with \: the \: higher \: specific \: heat.}$

Explanation:

HEAT:

In the universe there are only two mods of Transfer of Energy one is Heat and another is Work. That's why Heat and Work are well knowns Path function.

Specific Heat:

The specific Heat of any material is the heat gained or released by the material to raise or fall it's temperature by 1°C per unit mass of the material.

The heat gained or released (Q) is directly proportional to the mass of substance(m) and rise or fall of temp(∆T)

given by the equation,

$\sf \: s = \frac{Q}{m \Delta T}$

Where S is the proportionality constant also known as specific Heat.

S.I. unit of s is joule/kg-K

C.G.S unit is cal/gm °C.

Specific heat of water: s = 4200 J/kg°C

Coming to the next important term calorimeter,

Calorimeter:

We already knew above that heat is not a form of energy it's a mod of transfer of energy, consider One Energy converted from State A to State B then the total heat(Transferred energy) during the process is measured by a device known as Calorimeter.

Now, coming to your question.

Consider a metal, with lower specific heat (s), the equation we derived above tells that specific heat is directly proportional to energy per unit change in temperature, that means if specific heat will be low, lesser amount of Energy(Heat) will be produced which will cause the minor increase in the temperature.

Which is a contradiction hence the answer would be Metal with the higher specific heat.

This is the final answer!

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