Question

The perimeter of a rectangular painting is 298 centimeters. If the length of the painting is 94 centimeters, what is its width?

Answer 1

Step-by-step explanation:

Length = 94 cm

breadth = ?

Perimeter = 298 cm

Now..............

Perimeter = 2 ( l + b )

298cm = 2 ( 94 cm + b )

298 / 2 = 94 + b

149 cm = 94 + b

b = 149 - 94 cm

b = 55 cm

Answer 2

Answer:

• Value of it's width is 55 cm .

Step-by-step explanation:

In the question we have given perimeter of rectangular painting that is 298 cm , length of the painting is 94 cm , and we have asked to find the width of the rectangular painting . So perimeter of rectangle is ,

$\purple{ \boxed{Perimeter \: of \: rectangle = 2 ( l + w ) }}$

Where ,

• l = length of rectangle
• w = width of rectangle

Now , we are substituting value of length and equating it with given perimeter :

$\longrightarrow \: 2(94 + w) = 298$

Now, our last step is of calculations . So from here we are calculating ,

$\longrightarrow \: 94 + w = \frac{298}{2}$

$\longrightarrow \: 94 + w= 149$

$\longrightarrow \: w = 149 - 94$

$\longrightarrow \: \blue{\boxed{ \bold{w = 55 \:cm}}}$

• Therefore, width of rectangular painting is 55 cm .

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