The sequence an = 1 + (-3/7)^n is neither an arithmetic progression nor a geometric progression
The first ten terms of the sequence are 0.5714, 1.1837, 0.9213, 1.0337, 0.9855, 1.0062, 0.9973, 1.0011, 0.9995 and 1.0002
The nth term of the sequence is given as:
an = 1 + (-3/7)^n
The first ten terms are calculated as follows:
a1 = 1 + (-3/7)^1 = 0.5714
a2 = 1 + (-3/7)^2 = 1.1837
a3 = 1 + (-3/7)^3 = 0.9213
a4 = 1 + (-3/7)^4 = 1.0337
a5 = 1 + (-3/7)^5 = 0.9855
a6 = 1 + (-3/7)^6 = 1.0062
a7 = 1 + (-3/7)^7 = 0.9973
a8 = 1 + (-3/7)^8 = 1.0011
a9 = 1 + (-3/7)^9 = 0.9995
a10 = 1 + (-3/7)^10 = 1.0002
Read more about sequence at:
https://brainly.com/question/6561461