Question

$\rm \frac{ {10}^5 }{ {e}^{ \sqrt{e} } } \left( \int^{1}_0 {e}^{ \sqrt[]{ {e}^{x} } } \: dx + 2 \int_{e}^{ {e}^{ \sqrt{e} } } ln( ln(x) ) \: dx\right)$​

Answer 1

In the first integral, substitute $x \to e^{\sqrt{e^x}}$:

$\displaystyle I = \int_0^1 e^{\sqrt{e^x}} \, dx = 2 \int_e^{e^{\sqrt e}} \frac{dx}{\ln(x)}$

In the second integral, integrate by parts:

$\displaystyle J = \int_e^{e^{\sqrt e}} \ln(\ln(x)) \, dx = \dfrac12 e^{\sqrt e} - \int_e^{e^{\sqrt e}} \frac{dx}{\ln(x)}$

It follows that

$\dfrac{10^5}{e^{\sqrt e}}(I+2J) = \dfrac{10^5}{e^{\sqrt e}} \times e^{\sqrt e} = \boxed{10^5}$