Respuesta :
c^2 is GCF for Part A
= c^2(3x^2 + 2x - 1)
= c^2(3x - 1)(x + 1)
Part B
x^2 - 2x + 1
= x^2 - x - x + 1
= x(x - 1) - 1(x - 1)
= (x - 1)^2
Part c
x^2 - 64
= (x + 8)(x - 8)
= c^2(3x^2 + 2x - 1)
= c^2(3x - 1)(x + 1)
Part B
x^2 - 2x + 1
= x^2 - x - x + 1
= x(x - 1) - 1(x - 1)
= (x - 1)^2
Part c
x^2 - 64
= (x + 8)(x - 8)
Part A: I'm not sure I'm reading your question correctly.
Part B: (x-1)(x-1) or (x-1)^2
Part C: (x+8)(x+8) or (x+8)^2
Part B: (x-1)(x-1) or (x-1)^2
Part C: (x+8)(x+8) or (x+8)^2