Respuesta :

Answer:

[tex]x=7 + \sqrt{3}[/tex]

[tex]x=7 - \sqrt{3}[/tex]

Step-by-step explanation:

Given equation:

[tex]5x^2-70x=-230[/tex]

Divide both sides by 5:

[tex]x^2-14x=-46[/tex]

Square half of the coefficient of [tex]x[/tex]:  [tex](-14 \div 2)^2=49[/tex]
and add this to both sides:

[tex]x^2-14x+49=-46+49[/tex]

Factor the left side and simplify the right side:

[tex](x-7)^2=3[/tex]

Square root both sides:

[tex]x-7=\pm\sqrt{3}[/tex]

Add 7 to both sides:

[tex]x=7 \pm \sqrt{3}[/tex]

[tex]\sf x=\pm \sqrt{3}+7[/tex]

solving step wise:

[tex]\sf 5x^2-70x=-230[/tex]

divide the following by 5

[tex]\sf x^2-14x=-46[/tex]

completing square

[tex]\sf (x-\dfrac{14}{2})^2-(\dfrac{14}{2})^2 =-46[/tex]

should look like this

[tex]\sf (x-7)^2-49=-46[/tex]

simplify by changing sides

[tex]\sf x-7=\pm \sqrt{3}[/tex]

final answer:

[tex]\sf x=\pm \sqrt{3}+7[/tex]

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