Respuesta :
Answer:
[tex]x=7 + \sqrt{3}[/tex]
[tex]x=7 - \sqrt{3}[/tex]
Step-by-step explanation:
Given equation:
[tex]5x^2-70x=-230[/tex]
Divide both sides by 5:
[tex]x^2-14x=-46[/tex]
Square half of the coefficient of [tex]x[/tex]: [tex](-14 \div 2)^2=49[/tex]
and add this to both sides:
[tex]x^2-14x+49=-46+49[/tex]
Factor the left side and simplify the right side:
[tex](x-7)^2=3[/tex]
Square root both sides:
[tex]x-7=\pm\sqrt{3}[/tex]
Add 7 to both sides:
[tex]x=7 \pm \sqrt{3}[/tex]
[tex]\sf x=\pm \sqrt{3}+7[/tex]
solving step wise:
[tex]\sf 5x^2-70x=-230[/tex]
divide the following by 5
[tex]\sf x^2-14x=-46[/tex]
completing square
[tex]\sf (x-\dfrac{14}{2})^2-(\dfrac{14}{2})^2 =-46[/tex]
should look like this
[tex]\sf (x-7)^2-49=-46[/tex]
simplify by changing sides
[tex]\sf x-7=\pm \sqrt{3}[/tex]
final answer:
[tex]\sf x=\pm \sqrt{3}+7[/tex]