[tex] \frac{x^\frac{1}{2} }{x^\frac{2}{7}} [/tex]
According to the rule of exponents [tex] \frac{a^m}{a^n} = a^{(m-n)} [/tex] , i.e. when two terms are in division with same base , we subtract the exponents
So
[tex] \frac{x^\frac{1}{2} }{x^\frac{2}{7}} = x^{(\frac{1}{2}) - (\frac{2}{7})} [/tex]
[tex] =x^\frac{3}{14} [/tex]
Or
x to the 3 fourteenths power