Question

what is the surface area of a square pyramid with side length 2 yd and slant height 4 yd.

Answer 1

Answer:

20 yd^2.

Step-by-step explanation:

Area of base = 2^2 = 4 yd^2.

It has  4 side faces so:

Area of each triangular side = 1/2 * 2 * 4 = 4 yd^2

Total surface area = 4 + 4(4).

= 20 yd^2.