Find the value of x. Note that in the image below, mAED = 183° and mBD 73 1837 B TI E 73° O to O 128 55 73 60

The value of x in the intersection point of the secant and tangent is 55°.
when a tangent and a secant intersect then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.
Therefore,
x = 1 / 2 (arc AED - arc DB )
Therefore,
arc AED = 183°
arc DB = 73°
Therefore,
x = 1 / 2 (183 - 73)
x = 110 / 2
x = 55°
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