Question

For a 1.0×10−6 m solution of hno3(aq) at 25 °c, arrange the species by their relative molar amounts in solution.

Answer 1

The relative order of molar amounts since the solution is aqueoeus with H₂O having more concentration is; H₂O > H₃O⁺ = NO₃⁻ > OH⁻  > HNO₃

What is the relative molar amount?

Since the solution is aqueoeus, it means that H₂O has more concentration.

Now, since HNO₃ is a strong acid, it will completely dissociate. Thus;

HNO₃ + H₂O ⇒ H₃O⁺ + NO₃⁻

In the reaction above, HNO₃, H₂O, H₃O⁺, NO₃⁻ and OH⁻ are present. Since concentration of each ion is given as 1 * 10⁻⁶ M, then;

Concentration of OH⁻ is gotten from the formula;

k_w = [H₃O⁺][OH⁻]

Thus;

1 * 10⁻¹⁶ = [1 * 10⁻⁶] * [OH⁻]

[OH⁻] = [1 * 10⁻¹⁶]/[1 * 10⁻⁶]

[OH⁻] = 1 * 10⁻⁸

Thus, relative order of molar amount is;

H₂O > H₃O⁺ = NO₃⁻ > OH⁻  > HNO₃

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