Based on the calculations, the most likely value of t is equal to 2.2.
Given the following data:
A null hypothesis ([tex]H_0[/tex]) can be defined the opposite of an alternate hypothesis ([tex]H_a[/tex]) and it asserts that two (2) possibilities are the same.
For the one-tail test, we would reject the null hypothesis ([tex]H_0[/tex]) when the p-value is lesser than the value of [tex]\alpha[/tex];
[tex]H_o: P(Z > |\delta|) < 0.02[/tex]
For the two-tail test, we would fail to reject the null hypothesis ([tex]H_0[/tex]) when the p-value is greater than the value of [tex]\alpha[/tex];
[tex]H_o: 2P(Z > |z|) > 0.02\\\\H_o: P(Z > |z|) > 0.01[/tex]
Next, we would determine the positive value of z-score that satisfies this expression;
[tex]0.01 < P(Z < z) < 0.02\\\\[/tex]
From the z-table, we have:
[tex]P(Z > 2.326)\;and\; P(Z > 2.054)\\\\2.054 < z < 2.326[/tex]
Therefore, t = 2.2.
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