In the figure below, ABDC, EFHG, and ASHY are all squares; AB=1, EF=$, and AY=5.

What is the area of quadrilateral DYES?

In the figure below ABDC EFHG and ASHY are all squares AB1 EF and AY5 What is the area of quadrilateral DYES class=

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Answer:

16.97

Step-by-step explanation:

you need to find the length of DY (the hypotenuse of one of the triangles), and to do that, you need to find the length of CY, so subtract AB (which is 1) from AY (which is 5) and you are left with 4. then use the Pythagorean theorem to solve for DY. [tex]1^{2}[/tex] + [tex]4^{2}[/tex] = [tex]17^{2}[/tex]. [tex]\sqrt{17}[/tex] = 4.12 (rounded to the nearest hundredth). The last step is to solve for area, or length times height. The quadrilateral has equal side lengths, so the equation is

4.12 × 4.12 which equals 16.97

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