Respuesta :

Step-by-step explanation:

Use these equations.

Equation of a Hyperbola, centered at orgin

[tex] \frac{ {x}^{2} }{ {a}^{2} } - \frac{ {y}^{2} }{ {b}^{2} } = 1[/tex]

where a is the major axis

B is the minor axis.

Since a and X are first, the x axis is the major.

This also means the x axis contains the vertices and foci as well.

The equation of vertices when x is major axis is

[tex](x ±a)[/tex]

Since the vertices are (±1,0), and the orgin is (0,0). The length of a is 1.

So a=1.

The equation of foci is

[tex](x±c)[/tex]

Where c is formed by

[tex] {c}^{2} = {a}^{2} + {b}^{2} [/tex]

We know that c is 2 since the distance from the foci and center is 2. A is 1, so let find b.

[tex] {2}^{2} = {1}^{2} + {b}^{2} [/tex]

[tex]4 = 1 + {b}^{2} [/tex]

[tex]3 = {b}^{2} [/tex]

[tex] \sqrt{3} = {b}[/tex]

So our equation is

[tex] \frac{ {x}^{2} }{1 {}^{2} } - \frac{ {y}^{2} }{ (\sqrt{3}) {}^{2} } = 1[/tex]

[tex] \frac{ {x}^{2} }{1} - \frac{ {y}^{2} }{3} = 1[/tex]

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