Question

What is the magnetic force acting on an electron if its speed is 3.0 × 106 meters/second and the direction is perpendicular to a magnetic field of 0.020 teslas? The value of q = -1.6 × 10-19 coulombs.
F = 0 newtons
F = -6.0 × 10-15 newtons
F = -9.6 × 10-15 newtons
F = -3.0 × 10-16 newtons
F = -3.2 × 10-21 newtons

Answer 1

magnetic force equall q*v*b so is the answers are right?

Answer 2

I'm pretty sure this is the answer cause i had the same question and thins is the correct one. 

Fm= 9.60x10^-15 N