If number of cars recorded by Lynn is 1, 1, 2, 2, 2, and 4 cars then the mean absolute deviation of the number of cars is 0.7
The mean absolute deviation of a data set is the average of the absolute deviations from a central point .
Data we have is
1,1,2,2,2,4
Mean can be calculated as
[tex]&\text { Mean }=\frac{1+1+2+2+2+4}{6}\\ \\&\text { Mean }=\frac{12}{6} \\\\&\text { Mean }=2[/tex]
Absolute value between the data points and mean can be calculated as :
[tex]$\begin{aligned}&|1-2|=1 \\&|1-2|=1 \\&|2-2|=0 \\&|2-2|=0 \\&|2-2|=0 \\&|4-2|=2\end{aligned}$[/tex]
Now mean absolute deviation can be calculated as :
[tex]\begin{aligned}&\frac{1+1+0+0+0+2}{6} \\\\&=\frac{4}{6} \\\\&=0.66\end{aligned}$[/tex]
Rounding to nearest ten
mean absolute deviation=0.7
If number of cars recorded by Lynn is 1, 1, 2, 2, 2, and 4 cars then the mean absolute deviation of the number of cars is 0.7
To learn more about mean absolute deviation visit :https://brainly.com/question/17381861