Question

PHYSICS HELP!! NEED IT BY/ON MARCH 3!!
(a) A typical steam jet shoots 3. 62 kg of 157°C water vapor onto an intruder. How much energy is released by the cooling of the water vapor from 157°C down to the point where it can condense, 100°C? Specific heat of water vapor is 2020J/kg°C


(b) Once cooled how much heat is released by the condensation of the water vapor? The Latent Heat of Vaporization is 2,260,000 J/kg


(c) Now that the water is in liquid form, find how much more heat is released by the water as it cool to skin temperature of 26°C, then add the other energy to find the total heat released during the entire ordeal

Answer 1

From the calculations, the total heat involved in the entire process is 9.72 × 10^6 J.

What is specific heat capacity?

The term specific heat capacity is the heat that is gained when 1 Kg of a body undergoes a temperature rise of 1 K.

a) H = mcdT

m = mass

c = specific heat

dT = temperature change

H = 3.62 kg ×  2020J/kg°C × (157 - 100)

H = 416806.8 J

b) H = mL

H = 3.62 kg × 2,260,000 J/kg

H = 8181200 J

c) H = 3.62 kg × 4200 J/kg°C × ( 100 -26)

H = 1125096 J

Total heat: 416806.8 J + 8181200 J + 1125096 J = 9.72 × 10^6 J

Learn more about specific heat capacity: https://brainly.com/question/2530523