Answer:
x = 2[tex]\sqrt{6}[/tex]
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
x² = ([tex]\sqrt{12}[/tex] )² + ([tex]\sqrt{12}[/tex] )² [ the 2 legs are congruent ]
x² = 12 + 12 = 24 ( take square root of both sides )
x = [tex]\sqrt{24}[/tex] = [tex]\sqrt{4(6)}[/tex] = [tex]\sqrt{4}[/tex] × [tex]\sqrt{6}[/tex] = 2[tex]\sqrt{6}[/tex]
