Question

Molar mass of a compound is 90.07 g/mol. Determine its molecular formula if its empirical
formula is CH20

Answer 1

$\qquad$ ☀️$\pink{\bf{ {Answer = \: \: C_3H_6O_3 }}}$

For this question –

• Molar formula will be =$\bf {( CH_2O)}_n$

Now, let's find out value of n. Where–

$\qquad$ $\pink{\twoheadrightarrow\bf n = \dfrac{ Molar \:Mass }{Empirical \:Mass }}$

Empirical Mass of $\bf CH_2O$–

$\qquad$ $\twoheadrightarrow\sf 12 + 1×2 + 16$

$\qquad$ $\twoheadrightarrow\sf 30$

Now, we are given, mass of compound is 90.07 g/mol.

$\qquad$ $\twoheadrightarrow\bf n = \dfrac{ Molar\: Mass }{Empirical\: Mass }$

$\qquad$ $\twoheadrightarrow\sf n = \dfrac{90.07}{30}$

$\qquad$ $\twoheadrightarrow\sf n = \cancel{ \dfrac{90.07}{30}}$

$\qquad$ $\twoheadrightarrow\sf n = 3.0023$

$\qquad$ $\pink{\twoheadrightarrow\bf n = 3 }$

Molar formula will be –

$\qquad$ $\twoheadrightarrow\sf {( CH_2O)}_n$

$\qquad$ $\twoheadrightarrow\sf {( CH_2O)}_3$

$\qquad$ $\pink{\twoheadrightarrow\sf C_3H_6O_3}$

• Henceforth, Molar formula will be $\bf C_3H_6O_3$

Answer 2

The molecular formula of a compound whose empirical formula is CH20, is C3H6O3.

HOW TO CALCULATE MOLECULAR FORMULA?

The molecular formula of a compound can be calculated from the empirical formula as follows:

Empirical formula = CH2O.

(CH2O)n = 90.07g/mol

(12 + 2 + 16)n = 90.07

30n = 90.07

n = 3.00

If n = 3, the molecular formula of the compound will be (CH2O)3 = C3H6O3.

Therefore, molecular formula of a compound whose empirical formula is CH20, is C3H6O3.

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